CA Foundation 2026 · Paper 3 · Quantitative AptitudeQ37 · 1 mark↻ Appears in 2 of 6 yearsOfficial key verified
If mean of 5 observations x+1x+1, x+3x+3, x+5x+5, x+7x+7 and x+9x+9 is given as 125, then the value of xx will be.
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Mean =x+1+3+5+7+95=x+5=125⇒x=120=x+\dfrac{1+3+5+7+9}{5}=x+5=125\Rightarrow x=120.

Step 1 — Sum the observations

∑=(x+1)+(x+3)+(x+5)+(x+7)+(x+9)=5x+25.\sum=(x+1)+(x+3)+(x+5)+(x+7)+(x+9)=5x+25.

Step 2 — Set the mean equal to 125

Mean=5x+255=x+5=125.\text{Mean}=\frac{5x+25}{5}=x+5=125.

Step 3 — Solve

x=125−5=120.x=125-5=120. …

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