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Worked Examples · Example 27

Q.Insert 3 numbers between 1 and 256 so that the resulting sequence is a G.P.

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With 3 numbers inserted, the sequence has 5 terms in G.P.; find rr from ar4=256ar^4=256.

[!FORMULA] nn-th term: Tn=arn−1T_n=ar^{n-1}, where aa = first term, rr = common ratio.

  1. Total terms =3+2=5=3+2=5: 1, G1, G2, G3, 2561,\,G_1,\,G_2,\,G_3,\,256.
  2. Here a=1a=1 (first term) and T5=256T_5=256 (last term), so ar5−1=256 ⇒ r4=256ar^{5-1}=256\ \Rightarrow\ r^4=256.
  3. Solve r4=256=44 ⇒ r=4r^4=256=4^4\ \Rightarrow\ r=4 (taking the real positive root, as is standard for inserting means).
  4. G1=ar=1×4=4G_1=ar=1\times4=4. …

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