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Mathematics · Ch 6 — Applications of Vector Algebra

Geometric Introduction to Vectors

6.2

Geometric Introduction to Vectors

A vector v⃗\vec v is represented as a directed straight-line segment in 3-dimensional space R3\mathbb R^3: it has an initial point A=(a1,a2,a3)A=(a_1,a_2,a_3) and an end point B=(b1,b2,b3)B=(b_1,b_2,b_3), and is written AB⃗\vec{AB}. The length (magnitude) of AB⃗\vec{AB} is ∣AB⃗∣=(b1−a1)2+(b2−a2)2+(b3−a3)2|\vec{AB}|=\sqrt{(b_1-a_1)^2+(b_2-a_2)^2+(b_3-a_3)^2}, and its direction is the direction from AA to BB. A vector may be denoted interchangeably by v⃗\vec v or AB⃗\vec{AB}.

Equality of vectors. Two vectors AB⃗\vec{AB} and CD⃗\vec{CD} in R3\mathbb R^3 are equal, written AB⃗=CD⃗\vec{AB}=\vec{CD}, precisely when the length ∣AB∣|AB| equals the length ∣CD∣|CD| AND the direction from AA to BB is parallel to (and the same sense as) the direction from CC to DD. When this holds, CD⃗\vec{CD} is called a translate of AB⃗\vec{AB} — every vector can be translated anywhere in space to an equal copy with any chosen initial point.

Position vectors. If OO is the origin and P∈R3P\in\mathbb R^3 is any point, the vector OP⃗\vec{OP} is the position vector of PP. Every vector v⃗\vec v equals the position vector of exactly one point PP. We reserve the special notations i^,j^,k^\hat i,\hat j,\hat k for the position vectors of (1,0,0),(0,1,0),(0,0,1)(1,0,0),(0,1,0),(0,0,1) respectively, and 0⃗\vec 0 for the position vector of the origin (0,0,0)(0,0,0) — the unique vector of length 00 (its direction is unspecified / context-dependent). For a point (a1,a2,a3)(a_1,a_2,a_3), its position vector is a1i^+a2j^+a3k^a_1\hat i+a_2\hat j+a_3\hat k.

A vector of length 11 is a unit vector, written u^\hat u; note i^,j^,k^\hat i,\hat j,\hat k are themselves unit vectors. Real numbers used to scale vectors are called scalars.

Addition and scalar multiplication. For a⃗=a1i^+a2j^+a3k^\vec a=a_1\hat i+a_2\hat j+a_3\hat k, b⃗=b1i^+b2j^+b3k^\vec b=b_1\hat i+b_2\hat j+b_3\hat k and a scalar α∈R\alpha\in\mathbb R:

a⃗+b⃗=(a1+b1)i^+(a2+b2)j^+(a3+b3)k^,αa⃗=(αa1)i^+(αa2)j^+(αa3)k^.\vec a+\vec b=(a_1+b_1)\hat i+(a_2+b_2)\hat j+(a_3+b_3)\hat k,\qquad \alpha\vec a=(\alpha a_1)\hat i+(\alpha a_2)\hat j+(\alpha a_3)\hat k. …