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Q.The marks obtained by 9 students of a class are given below. Calculate mean deviation:
22, 65, 40, 50, 38, 20, 70, 25, 75

Assam AhsecAHSEC Assam Higher Secondary 1st Year Class 11 (Commerce) 2022Subjective· 4mImportance★★★★★est
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Mean = 405/9 = 45; mean deviation about mean = Σ|x−45|/9 = 160/9 = 17.78.

Step 1 — Arithmetic mean:

Σx = 22+65+40+50+38+20+70+25+75 = 405, n = 9.

Mean X̄ = 405/9 = 45.

Step 2 — Absolute deviations from the mean |x − 45|:

| x | |x − 45| |

|---|---|

| 22 | 23 |

| 65 | 20 |

| 40 | 5 |

| 50 | 5 |

| 38 | 7 |

| 20 | 25 |

| 70 | 25 |

| 25 | 20 |

| 75 | 30 |

| Σ = 405 | Σ|D| = 160 |

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