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Q.In how many ways can the natural numbers lying between 10 and 1000 be formed with the digits 0, 3, 5, 7, 9? OR How many 5-member committees can be formed from 8 teachers and 3 students so that a particular teacher is always selected for each committee?

Assam AhsecAHSEC Higher Secondary (HS) 1st Year Examination 2018Subjective· 3mImportance★★★★★
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Option 1: 120 such numbers. Option 2: 210 possible committees.

Option 1: Numbers between 10 and 1000 formed from digits {0,3,5,7,9}\{0,3,5,7,9\} (digits may repeat, as is standard for this counting problem) are either 2-digit or 3-digit numbers.

2-digit numbers: leading digit cannot be 00 (else it isn't a 2-digit number), so it has 44 choices (3,5,7,93,5,7,9); the units digit has all 55 choices. Total =4×5=20=4\times5=20.

3-digit numbers: leading digit has 44 choices (not 00), and each of the other two digits has 55 choices. Total =4×5×5=100=4\times5\times5=100.

Grand total: 20+100=12020+100=120.

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