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Q.Two lines passing through the point (2,3)(2, 3) intersect each other at an angle of 60∘60^\circ. If the slope of one line is 22. Find the equation of other line.

Assam AhsecAHSEC Higher Secondary (HS) 1st Year Examination 2026Subjective· 5mImportance★★★★★
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tan⁡60∘=3=∣m−21+2m∣\tan60^\circ=\sqrt3=\left|\frac{m-2}{1+2m}\right| gives two slopes; each with point (2,3)(2,3) gives y−3=m(x−2)y-3=m(x-2).

Let the other line have slope mm. The angle θ\theta between two lines of slopes mm and 22 satisfies

tan⁡θ=∣m−21+2m∣\tan\theta = \left|\dfrac{m - 2}{1 + 2m}\right|.

With θ=60∘\theta = 60^\circ, tan⁡60∘=3\tan60^\circ = \sqrt3:

∣m−21+2m∣=3\left|\dfrac{m-2}{1+2m}\right| = \sqrt3.

Case 1: m−21+2m=3⇒m−2=3(1+2m)⇒m−23m=2+3⇒m=2+31−23\dfrac{m-2}{1+2m} = \sqrt3 \Rightarrow m - 2 = \sqrt3(1+2m) \Rightarrow m - 2\sqrt3 m = 2 + \sqrt3 \Rightarrow m = \dfrac{2+\sqrt3}{1-2\sqrt3}.

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