Q.Explain Mendel's law of dominance using monohybrid cross.
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Start your 14-day free trial to unlock the full solution →Monohybrid cross TT x tt -> all tall F1 (Tt); F2 = 3 tall : 1 dwarf (genotype 1:2:1), proving dominance. OR: Plasmodium multiplies asexually in humans (liver + RBCs) and sexually in female Anopheles.
Mendel's Law of Dominance using a monohybrid cross (main question):
The Law of Dominance states that (i) characters are controlled by discrete units called factors (genes), (ii) factors occur in pairs (alleles), and (iii) in a dissimilar pair, one factor (dominant) expresses itself and masks the other (recessive).
Monohybrid cross (pea plant height):
- Parents (P): pure Tall (TT) x pure Dwarf (tt).
- Gametes: T and t.
- F1 generation: all Tt = Tall. Although the dwarf allele (t) is present, only the dominant Tall (T) is expressed — demonstrating dominance.
- F1 x F1 (self-pollination): Tt x Tt. Using a Punnett square, gametes T, t x T, t give:
- Genotypes: 1 TT : 2 Tt : 1 tt (ratio 1:2:1).
- Phenotypes: 3 Tall : 1 Dwarf (ratio 3:1).
- The dwarf trait, absent in F1, reappears in F2, proving that the recessive factor was not lost or blended — alleles remain discrete and separate, and one simply dominates the other in the heterozygote.
OR — Stages in the life cycle of the malarial parasite (Plasmodium):
The parasite is digenetic — needs two hosts.
- Infection of humans: an infected female Anopheles mosquito injects sporozoites into the human blood while biting.
- Liver (exo-erythrocytic) phase: sporozoites reach the liver, multiply asexually (schizogony), and release merozoites. …
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