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Q.Find the mean deviation about the median for the following data: 3,9,5,3,12,10,18,4,7,19,213, 9, 5, 3, 12, 10, 18, 4, 7, 19, 21.

Bihar BsebBihar Board Intermediate 1st Year 2025Subjective· 2mImportance★★★★★
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Mean deviation about the median ≈5.27\approx5.27.

Sort the data: 3,3,4,5,7,9,10,12,18,19,213,3,4,5,7,9,10,12,18,19,21 (n=11n=11, odd).

Median = middle (66th) value =9=9.

Absolute deviations from 99: ∣3−9∣=6, ∣3−9∣=6, ∣4−9∣=5, ∣5−9∣=4, ∣7−9∣=2, ∣9−9∣=0, ∣10−9∣=1, ∣12−9∣=3, ∣18−9∣=9, ∣19−9∣=10, ∣21−9∣=12|3-9|=6,\ |3-9|=6,\ |4-9|=5,\ |5-9|=4,\ |7-9|=2,\ |9-9|=0,\ |10-9|=1,\ |12-9|=3,\ |18-9|=9,\ |19-9|=10,\ |21-9|=12.

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