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Q.The equation of displacement of a particle executing simple harmonic motion is y = sin(12πt + π/4). Frequency of the particle is (A) 8 Hz
(B) 12 Hz
(C) 6 Hz
(D) 4 Hz

Bihar BsebBihar Board Intermediate 1st Year 2025MCQ· 1mImportance★★★★★
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The frequency of the given SHM is 6 Hz.

The given equation is y=sin⁡(12πt+π/4)y = \sin(12\pi t + \pi/4). Comparing with the standard SHM form y=Asin⁡(ωt+ϕ)y = A\sin(\omega t + \phi), the angular frequency is:

ω=12π rad/s\omega = 12\pi\text{ rad/s}

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