Q.Work is equal to:
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The Work-Energy Principle: From Intuition to Precision
Imagine pushing a heavy box across a rough floor. The harder you push and the farther it slides, the faster it moves when you let go. That connection — between the effort you put in (force × distance) and the change in the box's motion — is exactly what the Work-Energy Principle captures.
The Intuition First
Think of work as "energy transferred by a force." When you do work on an object, you're essentially pumping energy into it. That energy has to go somewhere — and in the simplest case, it shows up as a change in the object's speed. The object's kinetic energy (energy of motion) increases by exactly the amount of work you did.
This is why a car's brakes get hot: the work done by friction removes kinetic energy, turning it into thermal energy. The principle holds even when energy changes form.
The Precise Statement
Wnet=ΔK=Kf−Ki=21mvf2−21mvi2
Where:
- Wnet = net work done on the object (total work from all forces combined)
- K = kinetic energy = 21mv2
- m = mass, v = speed
The net work done on an object equals the change in its kinetic energy.
Why "Net Work" Matters
If you push a box forward while friction pulls it backward, only the net force matters. Suppose you push with 50 N and friction opposes with 30 N over 2 m:
- Work done by you: 50×2=100 J
- Work done by friction: −30×2=−60 J (negative because force opposes motion)
- Net work: 100−60=40 J
That 40 J is exactly the increase in the box's kinetic energy. The individual works don't matter — only the sum.
A Common Trap
The Work-Energy Principle applies to net work, not work done by a single force. A force can do positive work while the object slows down (if another force does even more negative work). Always find the total work from all forces.
When Does It Hold?
The principle works for:
- Any constant or varying force
- Straight-line or curved paths
- Objects that don't rotate (for now)
It fails if:
- The object deforms permanently (like crumpling a car) …
Only the component of force along the displacement does work, giving W = F·d cosθ. …
Work = F·d·cosθ.
Work done by a constant force F over a displacement d is the dot product W = F·d = Fd cosθ, where θ is the angle between the force and displacement.
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- CBSE 2023Set ANNUAL1 markMCQQ.If force and displacement of particle in the direction of force are doubled, then work done would be(a) double(b) 4 times(c) half(d) 1/4 times.
›Reveal solutionSolution
Work depends on the product of force and displacement, so doubling both quantities multiplies the work by 2×2=4.
Work done by a constant force is W=Fdcosθ, and here force and displacement are both along the same direction, so W=Fd. Let the original work be W1=Fd. When the force becomes 2F and the displacement becomes …
- CBSE 2023Set ANNUAL1 markMCQQ.One joule is equal to:(a) 1 kg × 1 m(b) 1 hp × 1 m(c) 1 N × 1 m(d) 1 N × 1 cm
›Reveal solutionSolution
1 joule = 1 newton × 1 metre.
Work = force × displacement (in the direction of force). Its SI unit is therefore newton-metre, called the joule.
…
- CBSE 2023Set ANNUAL1 markMCQQ.Work is equal to:(a) F × d(b) F × d sinθ(c) F × d cosθ(d) F × d tanθ
›Reveal solutionSolution
Work = F·d·cosθ.
Work done by a constant force F over a displacement d is the dot product W = F·d = Fd cosθ, where θ is the angle between the force and displacement.
…
- CBSE 2021Set ANNUAL1 markQ.The ................ of a body is defined as its capacity of doing work.
›Reveal solutionSolution
Energy is defined precisely as the capacity to do work; it is measured in the same units as work (joules in SI).
Energy is a scalar quantity that represents a body's or system's ability to perform work. A body possessing energy — whether kinetic (due to motion), potential (due to position/configuration), or another form — can do work on other bodies by …
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