Q.What is coefficient of restitution? Explain.
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🔒 Start your 14-day free trial to unlock the full solution →Concept understanding — Coefficient of Restitution
The Bounce: What Makes a Ball Bounce Back?
Drop a rubber ball and it springs back up. Drop a lump of clay and it just splats. The difference between these two extremes is captured by a single number: the coefficient of restitution (often written as e).
The intuition is simple. When two objects collide, they always deform a little — like a spring getting squashed. The question is: how much of that "squash" energy gets given back as motion? A perfect spring gives everything back; a lump of clay gives nothing back. The coefficient of restitution measures exactly that.
The Precise Definition
For any collision along a straight line (what we call head-on or one-dimensional collision), the coefficient of restitution is defined as:
e=Relative velocity of approachRelative velocity of separation
Let's unpack that. Suppose two balls, A and B, move toward each other. Before the collision, their velocities are uA and uB. After the collision, they are vA and vB.
The relative velocity of approach is how fast they are coming together: uA−uB (taking direction into account — if they move toward each other, this is positive).
The relative velocity of separation is how fast they are moving apart after the collision: vB−vA.
So the formula becomes:
e=uA−uBvB−vA
The coefficient of restitution is a dimensionless number (no units) that always lies between 0 and 1 for real collisions.
What the Numbers Mean
e=1 — Perfectly Elastic Collision
No kinetic energy is lost. The relative speed of separation equals the relative speed of approach. Think of two billiard balls or ideal gas molecules. The "spring" gives back everything.
e=0 — Perfectly Inelastic Collision
The objects stick together after impact. Their relative velocity of separation is zero. Think of two lumps of clay or a bullet embedding in a block. All the relative motion is lost.
0<e<1 — Partially Inelastic (Real World)
Every real collision falls here. A tennis ball against concrete might have e≈0.7; a basketball around 0.8. Some kinetic energy is lost as heat, sound, and permanent deformation.
A common mistake: thinking e depends on the masses of the colliding objects. It does not. e is a property of the materials and the geometry of the surfaces in contact. A steel ball bearing has roughly the same e whether it hits a small steel block or a large one.
Why "Along the Line of Impact" Matters
The definition includes the phrase "along the line of impact." In a glancing collision (like a pool ball hitting another at an angle), the velocities have components both along and perpendicular to the line joining the centers. The coefficient of restitution applies only to the velocity components along that line. The perpendicular components obey a different rule (usually, they are unchanged if friction is negligible).
A Quick Example …
Coefficient of restitution is a number between 0 and 1 that measures how elastic a collision between two bodies is. …
e measures how much relative speed survives a collision, compared to the value before it.
When two bodies collide, the coefficient of restitution is defined as the ratio of their relative velocity of separation (just after collision) to their relative velocity of approach (just before collision):
e=u1−u2v2−v1
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- CBSE 2026Set ANNUAL1 markMCQQ.For an Inelastic collision, what is the value of coefficient of restitution (e)?(a) e = 0(b) e = 1(c) 0 < e < 1(d) 0 > e > 1
›Reveal solutionSolution
For an inelastic collision, the coefficient of restitution e satisfies 0 < e < 1.
The coefficient of restitution is defined as e = (relative velocity of separation)/(relative velocity of approach) = (v2 − v1)/(u1 − u2). It measures how much kinetic energy is conserved in a collision. If e = 1, the collision is perfectly elastic (no kinetic energy lost, relative speed of approach equals relative speed of separation). If e = 0, the collision is perfectly inelastic (the bodies stick together after collision, no separ …
- CBSE 2025Set ANNUAL1 markMCQQ.For an elastic collision the coefficient of restitution(e) will be(a) e > 1(b) e < 1(c) e = 1(d) e = 0
›Reveal solutionSolution
The coefficient of restitution e is the ratio of relative speed of separation to relative speed of approach; for a perfectly elastic collision (KE conserved), e = 1.
e = (relative velocity of separation) / (relative velocity of approach)
For a perfectly elastic collision, kinetic energy is fully conserved and the relative speed of separation equals the relative speed of approach, giving e = 1.
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- CBSE 2024Set ANNUAL1 markMCQQ.On dropping from a height of 64 cm, a spherical ball jumps up to 36 cm. The coefficient of restitution of collision is (A) 2/3 (B) 3/4 (C) 64/36 (D) 9/16
›Reveal solutionSolution
e=h2/h1=36/64=3/4.
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- CBSE 2023Set ANNUAL1 markMCQQ.For perfectly elastic collision:(a) e = 1(b) e > 1(c) e < 1(d) e = 0
›Reveal solutionSolution
For a perfectly elastic collision, e = 1.
The coefficient of restitution e = (relative velocity of separation)/(relative velocity of approach).
- Perfectly elastic collision: kinetic energy conserved, e = 1. …
- CBSE 2022Set ANNUAL1 markMCQQ.In the case of perfectly elastic collision —(a) e = 1(b) e > 1(c) e < 1(d) e = 0
›Reveal solutionSolution
For a perfectly elastic collision, e = 1.
The coefficient of restitution is e=relative velocity of approachrelative velocity of separation.
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