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Q.Two springs A and B with spring constants respectively k1 and k2 are stretched to the same length. The ratio of potential energies stored (U_A/U_B) in them will be

(a) (k1/k2)^2
(b) 2k1/k2
(c) 2k2/k1
(d) k1/k2
Bihar BsebBihar Board Intermediate 1st Year 2026MCQ· 1mImportance★★★★★
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U = ½kx^2 with the same x gives U_A/U_B = k1/k2. Answer (D).

The potential energy stored in a stretched spring is U = ½ k x^2, where x is the extension.

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