The chemical reaction, 2O3 -- 3O2 proceeds as follows : O3 - O2 + O ( fast ) ; O + O3 - 2O2 (slow). Then the rate law expression of this reaction is

(a) Rate = K[O3]2
(b) Rate = K[O3]2[O2]-1
(c) Rate = K[O3][O2]
(d) Rate = K[O3][O2]2

Question

The chemical reaction, 2O3 --> 3O2 proceeds as follows : O3 -> O2 + O ( fast ) ; O + O3 -> 2O2 (slow). Then the rate law expression of this reaction is

(a) Rate = K[O3]2
(b) Rate = K[O3]2[O2]-1
(c) Rate = K[O3][O2]
(d) Rate = K[O3][O2]2

Accepted Answer

>

> [!TLDR]
> The slow (rate-determining) step gives Rate = k[O][O3]; substituting the O-atom concentration from the fast pre-equilibrium gives Rate = K[O3]^2[O2]^-1.
>
> Mechanism:
> - Step 1 (fast, equilibrium): O3 ⇌ O2 + O
> - Step 2 (slow, rate-determining): O + O3 → 2O2
>
> The overall rate is set by the slow step:
> Rate = k2 [O][O3]
>
> But [O] is a reactive intermediate; express it from the fast equilibrium. For step 1: …

Q.The chemical reaction, 2O3 --> 3O2 proceeds as follows : O3 -> O2 + O ( fast ) ; O + O3 -> 2O2 (slow). Then the rate law expression of this reaction is

Concept understanding — Rate Determining Step

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Q.The chemical reaction, 2O3 --> 3O2 proceeds as follows : O3 -> O2 + O ( fast ) ; O + O3 -> 2O2 (slow). Then the rate law expression of this reaction is

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