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Q.Lithium forms BCC crystal. Calculate the atomic radius of Lithium if the length of the side of a unit cell of Lithium is 351 pm.
Bihar BsebBihar Board Intermediate 2021Subjective· 2mImportance★★★★★
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Start your 14-day free trial to unlock the full solution →In a BCC lattice the atoms touch along the body diagonal, giving r = (√3/4)a = 152 pm for a = 351 pm.
In a body-centred cubic (BCC) unit cell, the corner atoms and the body-centre atom touch each other along the body diagonal of the cube.
Step 1 — Geometry of BCC:
Length of body diagonal = √3 x a (where a = edge length).
Along the body diagonal there are 4 atomic radii (r + 2r + r = 4r).
Therefore: 4r = √3 a
=> r = (√3 / 4) x a.
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