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Q.Evaluate the determinant ∣a−bb−cc−ab−cc−aa−bc−aa−bb−c∣\begin{vmatrix} a-b & b-c & c-a \\ b-c & c-a & a-b \\ c-a & a-b & b-c \end{vmatrix}.

Bihar BsebBihar Board Intermediate 2021Subjective· 2mImportance★★★★★
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Each row (and column) sums to zero, so C1+C2+C3C_1+C_2+C_3 gives a zero column and the determinant is 00.

Let Δ=∣a−bb−cc−ab−cc−aa−bc−aa−bb−c∣.\Delta=\begin{vmatrix} a-b & b-c & c-a \\ b-c & c-a & a-b \\ c-a & a-b & b-c \end{vmatrix}.

Step 1 — Column operation C1→C1+C2+C3C_1\to C_1+C_2+C_3. Add all three columns. In every row the entries sum to

(a−b)+(b−c)+(c−a)=0.(a-b)+(b-c)+(c-a)=0.

So the new first column is (000).\begin{pmatrix}0\\0\\0\end{pmatrix}.

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