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Q.Find the inverse matrix of the following matrix: [4123]\begin{bmatrix} 4 & 1 \\ 2 & 3 \end{bmatrix}.

Bihar BsebBihar Board Intermediate 2026Subjective· 2mImportance★★★★★
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For a 2×22\times2 matrix, A−1=1det⁡A adj(A)A^{-1} = \dfrac{1}{\det A}\,\text{adj}(A). Here det⁡A=10\det A = 10.

Let A=[4123]A = \begin{bmatrix} 4 & 1 \\ 2 & 3 \end{bmatrix}.

Step 1 — determinant:

det⁡A=(4)(3)−(1)(2)=12−2=10≠0,\det A = (4)(3) - (1)(2) = 12 - 2 = 10 \neq 0,

so A−1A^{-1} exists.

Step 2 — adjoint (swap the diagonal entries, negate the off-diagonal ones):

adj(A)=[3−1−24].\text{adj}(A) = \begin{bmatrix} 3 & -1 \\ -2 & 4 \end{bmatrix}.

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