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Q.Solve: y(1+xy) dx−x dy=0y(1 + xy)\,dx - x\,dy = 0.

Bihar BsebBihar Board Intermediate 2021Subjective· 2mImportance★★★★★
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Rearrange into an exact form: the combination y dx−x dyy\,dx-x\,dy is y2 d ⁣(xy)y^2\,d\!\left(\tfrac{x}{y}\right).

Given y(1+xy) dx−x dy=0,y(1+xy)\,dx-x\,dy=0, i.e. y dx+xy2 dx−x dy=0.y\,dx+xy^2\,dx-x\,dy=0.

Step 1 — Group terms.

(y dx−x dy)+xy2 dx=0 ⇒ (y dx−x dy)=−xy2 dx.(y\,dx-x\,dy)+xy^2\,dx=0\ \Rightarrow\ (y\,dx-x\,dy)=-xy^2\,dx.

Step 2 — Divide by y2y^2. Recall d ⁣(xy)=y dx−x dyy2.d\!\left(\dfrac{x}{y}\right)=\dfrac{y\,dx-x\,dy}{y^2}. So …

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