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Q.∫−π/2π/2∣cos⁡x∣ dx=\int_{-\pi/2}^{\pi/2} |\cos x|\,dx =

(a) 22
(b) 11
(c) 00
(d) 44
Bihar BsebBihar Board Intermediate 2021MCQ· 1mImportance★★★★★
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∫−π/2π/2∣cos⁡x∣ dx=2\displaystyle\int_{-\pi/2}^{\pi/2} |\cos x|\,dx = 2.

On the interval [−π2,π2]\left[-\dfrac{\pi}{2},\dfrac{\pi}{2}\right], cos⁡x≥0\cos x \ge 0, so ∣cos⁡x∣=cos⁡x|\cos x| = \cos x. Also cos⁡x\cos x is even, so …

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