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Q.The direction ratios of two straight lines are l,m,nl, m, n and l1,m1,n1l_1, m_1, n_1. The lines will be perpendicular to each other if

(a) ll1=mm1=nn1\frac{l}{l_1} = \frac{m}{m_1} = \frac{n}{n_1}
(b) ll1+mm1+nn1=0\frac{l}{l_1} + \frac{m}{m_1} + \frac{n}{n_1} = 0
(c) l2+m2+n2=l12+m12+n12l^2 + m^2 + n^2 = l_1^2 + m_1^2 + n_1^2
(d) ll1+mm1+nn1=0ll_1 + mm_1 + nn_1 = 0
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Perpendicular lines ⇒ll1+mm1+nn1=0\Rightarrow ll_1 + mm_1 + nn_1 = 0.

The angle θ\theta between two lines with direction ratios l,m,nl, m, n and l1,m1,n1l_1, m_1, n_1 satisfies

cos⁡θ=ll1+mm1+nn1l2+m2+n2 l12+m12+n12.\cos\theta = \frac{ll_1 + mm_1 + nn_1}{\sqrt{l^2+m^2+n^2}\,\sqrt{l_1^2+m_1^2+n_1^2}}. …

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