CA Foundation 2025 · Paper 3 · Quantitative AptitudeQ76 · 1 mark↻ Appears in 2 of 6 yearsOfficial key verified
Find the Coefficient of variation for the following numbers :
Figure for question 76
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CV = (SD ÷ Mean) × 100 = (2 ÷ 6) × 100 = 33.33%.

Step 1 — Mean

Data: 7, 5, 9, 3, 6.

xˉ=7+5+9+3+65=305=6\bar x = \frac{7+5+9+3+6}{5} = \frac{30}{5} = 6

Step 2 — Standard deviation

Deviations from 6: 1,−1,3,−3,01, -1, 3, -3, 0; squared: 1,1,9,9,01, 1, 9, 9, 0, sum =20= 20.

σ=∑(x−xˉ)2n=205=4=2\sigma = \sqrt{\frac{\sum (x-\bar x)^2}{n}} = \sqrt{\frac{20}{5}} = \sqrt{4} = 2

Step 3 — Coefficient of variation

CV=σxˉ×100=26×100=33.33%CV = \frac{\sigma}{\bar x}\times 100 = \frac{2}{6}\times 100 = 33.33\% …

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