CA Foundation 2025 · Paper 3 · Quantitative AptitudeQ75 · 1 mark↻ Appears in 3 of 6 yearsOfficial key verified
Find the Harmonic Mean of 2, 4 & 6.
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HM=n∑(1/x)=311/12=3611≈3.27≈3.30HM=\dfrac{n}{\sum(1/x)}=\dfrac{3}{11/12}=\dfrac{36}{11}\approx3.27\approx3.30.

Step 1 — Harmonic mean formula

HM=n∑1xiHM = \dfrac{n}{\sum \dfrac{1}{x_i}}

Step 2 — Sum the reciprocals

12+14+16=6+3+212=1112.\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{6} = \dfrac{6+3+2}{12} = \dfrac{11}{12}.

Step 3 — Divide

HM=311/12=3×1211=3611≈3.27.HM = \dfrac{3}{11/12} = 3\times\dfrac{12}{11} = \dfrac{36}{11} \approx 3.27.

The nearest given value is 3.303.30.

Why the other options are wrong: 3.003.00 (B) would only arise from a different set; 4.004.00 (D) is the arithmetic mean; 3.753.75 (C) does not match the reciprocal computation. (Recall HM≤GM≤AMHM\le GM\le AM; here AM=4AM=4, so HM<4HM<4, ruling out (D).) …

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