CA Foundation 2025 · Paper 3 · Quantitative AptitudeQ72 · 1 mark↻ Appears in 2 of 6 yearsOfficial key verified
For a distribution the mean is 30. The standard deviation is 2, then coefficient of variation is
Figure for question 72
Single correct — pick one, then checkICAI format
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

CV=σxˉ×100=230×100=6.67%CV=\dfrac{\sigma}{\bar{x}}\times100=\dfrac{2}{30}\times100=6.67\%.

Step 1 — Formula for coefficient of variation

CV=σxˉ×100%CV = \dfrac{\sigma}{\bar{x}}\times 100\%

Step 2 — Substitute the given values

With standard deviation σ=2\sigma=2 and mean xˉ=30\bar{x}=30:

CV=230×100=20030=6.67%.CV = \dfrac{2}{30}\times100 = \dfrac{200}{30} = 6.67\%.

Why the other options are wrong: 7.5%7.5\% (C) comes from 302\tfrac{30}{2} or a mis-division; 2.5%2.5\% (D) forgets to divide by the mean correctly; 9.45%9.45\% (B) does not follow from the data. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.

← Back to the Paper 3 · Quantitative Aptitude 2025 paper