CA Foundation 2026 · Paper 3 · Quantitative AptitudeQ2 · 1 mark↻ Appears in 3 of 6 yearsOfficial key verified
The solution of the inequality 5−2x3≤x6−5\dfrac{5-2x}{3}\le\dfrac{x}{6}-5 is
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Multiplying 5−2x3≤x6−5\dfrac{5-2x}{3}\le\dfrac{x}{6}-5 by 6 gives 40≤5x40\le 5x, i.e. x≥8x\ge 8.

Step 1 — clear denominators (LCM = 6)

6⋅5−2x3≤6(x6−5) ⇒ 2(5−2x)≤x−30.6\cdot\frac{5-2x}{3}\le 6\left(\frac{x}{6}-5\right)\ \Rightarrow\ 2(5-2x)\le x-30.

Step 2 — expand and collect

10−4x≤x−30 ⇒ 10+30≤x+4x ⇒ 40≤5x.10-4x\le x-30\ \Rightarrow\ 10+30\le x+4x\ \Rightarrow\ 40\le 5x.

Step 3 — isolate xx

x≥8.x\ge 8.

Dividing by the positive 55 keeps the inequality sign unchanged. …

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