CA Foundation 2025 · Paper 3 · Quantitative AptitudeQ21 · 1 mark↻ Appears in 6 of 6 yearsOfficial key verified
How much approximate amount should you save annually to accumulate ₹ 20,00,000 by the end of 12 years, if the saving earns an interest of 14 percent compound annually ? [Given that (1.14)12=4.8179(1.14)^{12} = 4.8179]
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Annual saving = Target ÷ annuity accumulation factor = ₹20,00,000 ÷ 27.27 ≈ ₹73,339.

Step 1 — Recognise the sinking fund (FV of annuity)

Equal yearly deposits compounding to reach a fixed future target is a sinking-fund problem. The accumulated value of an ordinary annuity is

FV=P×(1+i)n−1iFV = P\times\dfrac{(1+i)^n-1}{i}

Step 2 — Substitute the data

FV=20,00,000FV=20{,}00{,}000, i=0.14i=0.14, n=12n=12, (1.14)12=4.8179(1.14)^{12}=4.8179.

(1+i)n−1i=4.8179−10.14=3.81790.14=27.2707\dfrac{(1+i)^n-1}{i}=\dfrac{4.8179-1}{0.14}=\dfrac{3.8179}{0.14}=27.2707

Step 3 — Solve for the annual saving

P=FV27.2707=20,00,00027.2707≈₹73,339P=\dfrac{FV}{27.2707}=\dfrac{20{,}00{,}000}{27.2707}\approx ₹73{,}339 …

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