CA Foundation 2026 · Paper 3 · Quantitative AptitudeQ6 · 1 mark↻ Appears in 5 of 6 yearsOfficial key verified
If the difference between the annually compounded interest and simple interest on a certain sum of money at 8% per annum for 3 years is ₹ 788. Then the principle amount is ______.
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Use the 3-year difference formula CI−SI=P[(1+r)3−1−3r]CI-SI=P[(1+r)^3-1-3r]; solving 788=P(0.019712)788=P(0.019712) gives P≈₹39,975P\approx ₹39{,}975.

Step 1 — Write the difference formula

For 33 years the difference between compound interest and simple interest is:

CI−SI=P[(1+r)3−1−3r]CI-SI=P\big[(1+r)^3-1-3r\big]

where rr is the rate per rupee.

Step 2 — Substitute r=0.08r=0.08

(1.08)3=1.259712(1.08)^3=1.259712

(1+r)3−1−3r=1.259712−1−0.24=0.019712(1+r)^3-1-3r=1.259712-1-0.24=0.019712

Step 3 — Solve for the principal

788=P×0.019712788=P\times 0.019712

P=7880.019712≈₹39,975P=\frac{788}{0.019712}\approx ₹39{,}975 …

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