CA Foundation 2024 · Paper 3 · Quantitative AptitudeQ21 · 1 mark↻ Appears in 6 of 6 yearsOfficial key verified
What is the annual contribution required by an organization to accumulate ₹ 20,00,000 in ten years for the construction of a new manufacturing plant, utilizing a sinking fund with an annual interest rate of 6% compounded annually ?
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Annual deposit = Target ÷ future-value-of-annuity factor = ₹20,00,000 ÷ 13.180785 = ₹1,51,736.03.

Step 1 — The sinking-fund relation

Each year an equal amount PP is set aside and earns 6% compounded annually. After 10 years the deposits accumulate to the future value of an ordinary annuity:

FV=P×(1+i)n−1i=P×A(n,i)FV = P \times \dfrac{(1+i)^n - 1}{i} = P \times A(n,i)

Step 2 — Substitute the known values

Here the target FV=₹20,00,000FV = ₹20{,}00{,}000 and the factor A(10,0.06)=13.180785A(10, 0.06) = 13.180785 is supplied.

P=FVA(10,0.06)=20,00,00013.180785P = \dfrac{FV}{A(10,0.06)} = \dfrac{20{,}00{,}000}{13.180785}

Step 3 — Compute the deposit

P=₹1,51,736.03P = ₹1{,}51{,}736.03 …

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