CA Foundation 2026 · Paper 3 · Quantitative AptitudeQ70 · 1 markOfficial key verified
In a class, 50 students have expressed that they like Mathematics, while 66 students like Accountancy. Among these, 36 students like both Mathematics and Accountancy. Based on this information, determine how many students in the class like either Mathematics or Accountancy?
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Union of two sets: n(M∪A)=n(M)+n(A)−n(M∩A)=50+66−36=80n(M\cup A) = n(M)+n(A)-n(M\cap A) = 50+66-36 = 80.

Step 1 — Inclusion–exclusion principle

Adding the two group sizes double-counts the students in both, so subtract the overlap once:

n(M∪A)=n(M)+n(A)−n(M∩A)n(M \cup A) = n(M) + n(A) - n(M \cap A)

Step 2 — Substitute

n(M)=50n(M)=50 (Mathematics), n(A)=66n(A)=66 (Accountancy), n(M∩A)=36n(M\cap A)=36 (both):

n(M∪A)=50+66−36=80n(M \cup A) = 50 + 66 - 36 = 80

Why the other options are wrong: (A) 14 and (B) 20 are the “only one subject” counts (50−36=1450-36=14, 66−36=3066-36=30 region pieces); (C) 52 forgets to subtract the overlap fully; only 80 is the full union. …

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