CA Foundation 2026 · Paper 3 · Quantitative AptitudeQ71 · 1 markOfficial key verified
Relation on integers is defined by :
Figure for question 71
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Divisibility of a−ba-b by 5 is congruence mod 5 — reflexive, symmetric and transitive — hence an equivalence relation.

Step 1 — Reflexive?

For any integer aa, a−a=0=5×0a-a = 0 = 5\times0 is divisible by 5, so aRaaRa holds. Reflexive ✓

Step 2 — Symmetric?

If a−b=5ka-b = 5k for some integer kk, then b−a=−5k=5(−k)b-a = -5k = 5(-k) is also divisible by 5, so bRabRa. Symmetric ✓

Step 3 — Transitive?

If a−b=5ka-b=5k and b−c=5mb-c=5m, then a−c=(a−b)+(b−c)=5(k+m)a-c = (a-b)+(b-c) = 5(k+m) is divisible by 5, so aRcaRc. Transitive ✓

Since all three properties hold, RR is an equivalence relation.

Why the other options are wrong: (A), (B) and (D) each claim only some properties fail, but the checks above show all three hold simultaneously. …

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