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Applied Mathematics · Class 12 Commerce

CBSE Class 12 Applied Mathematics — Real Previous-Year Papers

with complete answers

Real previous-year board papers, year by year — the official exam pattern, the full question paper, and every question solved the concept-first way. Distinct from the chapter-wise textbook bank.

2022–2025
Years of papers
6
Total Papers
6
Real Board Papers
0
Sample papers
204
Real-paper Q & A
0
Sample-paper Q & A

Real board-paper questions available, by year

—2026Paper not yet available
76 Q20252 sets
76 Q20242 sets
38 Q2023complete
14 Q2022COVID Term-2 · 1 sets
—2021No exam held

Shown as extracted / official per paper (38 from 2023, 36 earlier). Years with multiple CBSE series sets show total questions across all sets (each set is a full paper); some counts read higher because OR-choices & case-study sub-parts are counted separately.

2026 — Paper not yet available: The 2026 CBSE Applied Mathematics exam was held (9 March 2026) and the official marking scheme is available, but the question paper has not yet been published in a form we can verify against a real printed original. We publish only a paper we can confirm against a genuine source — it will appear here once that is available.

2021 — No exam held: Applied Mathematics (241) is a newer CBSE elective — its first Class-12 cohort sat the board exam in 2022, so no 2021 Applied Mathematics paper was ever set. (The 2021 Class-12 board exams were in any case cancelled nationwide due to COVID-19.)

CBSE Class XII Board 2025 (Supplementary) · Set 465/S/WXYZ/4

Real board examination
Sets

About this paper

The real Class-12 board examination held in 2025. Every question below is solved the concept-first way. Sample papers are labelled honestly — never shown as a past exam.

Total marks
—
Questions
—
Duration
—
Sections
—

The marks / questions / duration above are the official exam pattern. We currently have 38 of this paper’s questions, with 38 fully solved. Questions we couldn’t yet extract or verify are held — never shown as complete.

The question paper

The questions we hold for this paper, laid out by section. Solutions are on the Answers tab.

Board Examination

Applied Mathematics

CBSE Class XII Board 2025 (Supplementary) · Set 465/S/WXYZ/4

Series/Set: 465/S/WXYZ/4Roll No. ________
Time Allowed: —Maximum Marks: —
Section A

Q1.
The smallest positive integer (mod 11) to which 282 is congruent, is : (A) 3 (B) 7 (C) 9 (D) 17
[1]
Q2.
A man can row 6 km/h in still water. It takes him twice as long to row up as to row down the river. Then, the speed of the stream is : (A) 2 km/h (B) 4 km/h (C) 6 km/h (D) 8 km/h
[1]
Q3.
If ∣x+1∣x+1>0,x∈R\dfrac{|x+1|}{x+1} > 0, x \in R, then (A) x∈[−1,∞)x \in [-1, \infty) (B) x∈(−1,∞)x \in (-1, \infty) (C) x∈(−∞,−1)x \in (-\infty, -1) (D) x∈(−∞,−1]x \in (-\infty, -1]
[1]
Q4.
If P=[1021]P = \begin{bmatrix}1 & 0\\2 & 1\end{bmatrix}, Q=[x011]Q = \begin{bmatrix}x & 0\\1 & 1\end{bmatrix} and P=Q2P = Q^2, then x equals : (A) ±1\pm 1 (B) −1-1 (C) 11 (D) 22
[1]
Q5.
If A is an invertible matrix, then which of the following is notnot true ? (A) ∣A−1∣=∣A∣−1|A^{-1}| = |A|^{-1} (B) (A2)−1=(A−1)2(A^2)^{-1} = (A^{-1})^2 (C) (A′)−1=(A−1)′(A')^{-1} = (A^{-1})' (D) ∣A∣≠0|A| \neq 0
[1]
Q6.
The system of linear equations 2x+ky=72x + ky = 7 3x+2y=73x + 2y = 7 will be consistent, if : (A) k=43k = \dfrac{4}{3} (B) k≠43k \neq \dfrac{4}{3} (C) k≠34k \neq \dfrac{3}{4} (D) k=34k = \dfrac{3}{4}
[1]
Page 1 of 6
Q7.
If y = xy, then (dy)/(dx) is : (A) xy (log x + 1) (B) (y²)/(x(1 + y log x)) (C) xy (log x - 1) (D) (y²)/(x(1 - y log x))
[1]
Q8.
The function f(x) = ax is increasing on R, if : (A) a > 0 (B) a > 1 (C) a < 0 (D) 0 < a < 1
[1]
Q9.
A function f : R → R is defined as f(x) = x³ + 1. The function f has : (A) no maximum value (B) no minimum value (C) both maximum and minimum values (D) neither maximum nor minimum value
[1]
Q10.
The relation between “Marginal Cost (MC)” and “Average Cost (AC)” of producing ‘x’ units of a product is : (A) (d)/(dx)(AC) = x(MC - AC) (B) (d)/(dx)(AC) = x(AC - MC) (C) (d)/(dx)(AC) = (1)/(x)(MC - AC) (D) (d)/(dx)(AC) = (1)/(x)(AC - MC)
[1]
Q11.
For a random variable X, E(X) = 3 and E(X²) = 11. The variance of X is : (A) 8 (B) 5 (C) 2 (D) 1
[1]
Q12.
If the mean and standard deviation of a binomial distribution are 12 and 2 respectively, then the value of the parameter p is : (A) (5)/(6) (B) (1)/(6) (C) (1)/(3) (D) (2)/(3)
[1]
Q13.
If the variance of a Poisson distribution is 2, then P(X = 2) is : (A) 4e² (B) 2e² (C) (2)/(e²) (D) (4)/(e²)
[1]
Q14.
Normal distribution is symmetric about : (A) Variance (B) Co-variance (C) Mean (D) Standard deviation
[1]
Q15.
Using the flat rate method, the EMI to repay a loan of ₹ 20,000 in 2(1)/(2) years at an interest rate of 8% per annum is : (A) ₹ 100 (B) ₹ 700 (C) ₹ 800 (D) ₹ 1,000
[1]
Q16.
The graph of the inequality 3x + 2y > 6 is the : (A) entire XOY plane (B) whole XOY plane excluding the points on the line 3x + 2y = 6 (C) half plane that contains the origin (D) half plane that neither contains the origin nor the points on the line 3x + 2y = 6
[1]
Page 2 of 6
Q17.
The straight line trend is represented by the equation : (A) y = a + bx (B) y = a - bx (C) y = na + b Σ x (D) y = na - b Σ x
[1]
Q18.
If for the purpose of t-test of significance, a random sample of size (n) 34 is drawn from a normal population, then the degree of freedom (N) is : (A) 32 (B) 33 (C) 35 (D) 36
[1]
Q19.
Assertion (A) : Solution set of inequality |3x - 2| ≤ (1)/(2), x ∈ R is [(1)/(2), (5)/(6)]. Reason (R) : |x - a| ≤ r Leftrightarrow x ≤ a - r or x ≥ a + r. (A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A). (B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A). (C) Assertion (A) is true, but Reason (R) is false. (D) Assertion (A) is false, but Reason (R) is true.
[1]
Q20.
Assertion (A) : Matrix A = 0 -6 7; 6 5 -1; -7 1 0 is a skew-symmetric matrix. Reason (R) : A matrix A is skew-symmetric if A' = -A. (A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A). (B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A). (C) Assertion (A) is true, but Reason (R) is false. (D) Assertion (A) is false, but Reason (R) is true.
[1]
Section B

Q1.
(a) Two pipes P and Q together can fill a tank in 10 minutes. If pipe P takes 15 minutes less than Q to fill the tank alone, then find the time taken by pipe Q to fill the tank alone. OR (b) In a 200 m race, A beats B by 35 m or 7 seconds. Find the time taken by A to complete the race.
[2]
Q2.
Find the probability distribution of a number of successes in two tosses of a die, where a success is defined as getting a number greater than 4.
[2]
Q3.
Suppose that a 95% confidence interval states that population mean is greater than 100 and less than 300. How would you interpret this statement ?
[2]
Page 3 of 6
Q4.
Fill in the blanks : (a) t-distribution curve is symmetrical about the line _____. (b) The variable t of t-distribution lies between _____. (c) The mean of the t-distribution is _____. (d) The variance of the t-distribution is _____.
[2]
Q5.
(a) Find the present value of a perpetuity of ₹ 4,200 payable at the beginning of each year, if money is worth 5% compounded annually. OR (b) Find the present value of a perpetuity of ₹ 5,000 payable at the end of each year, if money is worth 5% compounded annually.
[2]
Section C

Q1.
(a) Prove that x+y x x; 5x+4y 4x 2x; 10x+8y 8x 3x = x³ OR (b) Prove that y+z z y; z z+x x; y x x+y = 4xyz
[3]
Q2.
Find the inverse (if it exists) of the matrix A = 1 2 -2; -1 3 0; 0 -2 1 .
[3]
Q3.
(a) Prove that the function f(x) = x² - x + 1 is neither strictly increasing nor strictly decreasing on the interval (-1, 1). OR (b) Find (dy)/(dx), if yx + xy + xx = ab.
[3]
Q4.
(a) A person invested ₹ 5,000 in a fund for 5 years. The value of the investment was ₹ 4,800 at the end of the second year, ₹ 6,000 at the end of the third year, ₹ 6,700 at the end of the fourth year and on maturity, the final investment sold at ₹ 8,000. Find the CAGR. [Use (1·6)(1)/(5) = 1·098] OR (b) The annual depreciation of an asset is ₹ 50,000 and its scrap value after useful life of 10 years is ₹ 60,000. Find the original cost of the asset, using linear depreciation method.
[3]
Page 4 of 6
Q5.
(a) Find : ∫ (dx)/((x+1)² (x²+1)) OR (b) Solve the differential equation : (dy)/(dx) = ex-y + x² e-y
[3]
Q6.
Minimise Z = 5x + 10y, subject to the constraints x + 2y ≤ 120 x + y ≥ 60 x - 2y ≥ 0 x, y ≥ 0
[3]
Section D

Q1.
Solve for x : 1 ≤ |x - 2| ≤ 3
[5]
Q2.
(a) A given rectangular area is to be fenced off in a field whose length lies along a straight river. If no fencing is needed along the river, show that the least length of fencing will be required when the length of the rectangular area is twice its breadth. OR (b) Solve the differential equation : x (dy)/(dx) + 2y = x² log x
[5]
Q3.
(a) Fit a straight line trend by the method of least squares to the following data and find the trend values. | Year | 2010 | 2012 | 2013 | 2014 | 2015 | 2016 | 2019 | |---|---|---|---|---|---|---|---| | Sales (in lakh ₹) | 65 | 68 | 70 | 72 | 75 | 67 | 73 | OR (b) Find the trend values by taking 4-yearly moving averages for the following data. | Year | 2015 | 2016 | 2017 | 2018 | 2019 | 2020 | 2021 | 2022 | |---|---|---|---|---|---|---|---|---| | Sales (in thousand ₹) | 108 | 112 | 110 | 120 | 140 | 120 | 100 | 135 |
[5]
Page 5 of 6
Q4.
A machine costs a company ₹ 52,000 and its effective life is estimated to be 25 years. A sinking fund is created for replacing the machine by a new model at the end of its life time, when its scrap realizes a sum of ₹ 2,500 only. The price of the new model is estimated to be 25% more than the price of the present one. Find what amount should be set aside at the end of each year out of the profits for the sinking fund, if it accumulates at 3·5\% per annum compound. [Given (1·035)²⁵ = 2·3632]
[5]
Section E

Q1.
According to an educational board survey, it was observed that class XII students apply at least one to four weeks ahead of college application deadlines. Let X represent the week when an average student applies ahead of a college’s application deadline and the probability of the student to get admission in the college P(X = x) is given as follows : P(X = x) = (kx)/(6), when x = 0, 1 or 2; [2mm]((1-k)x)/(6), when x = 3; [2mm](kx)/(2), when x = 4; [2mm]0, when x > 4 where k is a real number. Based on the above information, answer the following questions : (i) Determine the value of k. (ii) What is the probability that Mahesh will get admission in the college, given that he applied at least 3 weeks ahead of application deadline ? (iii) (a) Calculate the mathematical expectation of number of weeks taken by a student to apply ahead of a college’s application deadline. OR (iii) (b) To promote early admissions, the college is offering scholarships to the students for applying ahead of deadline as follows : ₹ 50,000 for applying 4 weeks ahead ₹ 20,000 for applying 3 weeks ahead ₹ 12,000 for applying 2 weeks ahead and ₹ 9,600 for applying 1 week ahead Determine the expected scholarship offered by the college.
[4]
Q2.
The feasible region for an LPP is shown in the graph given below : The graph shows the constraint line CD through C(0, 6) and D(12, 0), the line EF through E(0, 4) and F(5, 0), and the line through A(0, 12) and D(12, 0); the shaded feasible region is the quadrilateral with vertices C(0, 6), the interior intersection X, B (on the x-axis near x=6) and E(0, 4). Based on the above information, answer the following questions : (i) Determine the equation of CD. (ii) Determine the equation EF. (iii) (a) Determine all the constraints for the LPP. OR (iii) (b) Find the maximum value of the objective function Z = 600x + 400y.
[4]
Q3.
A man took a home loan of ₹ 40,00,000 from a bank at the interest of 6·75\% per annum compounded monthly which is to be amortized by equal payments at the end of each month for 10 years. Based on the above information, answer the following questions : (i) Find the monthly instalment. [Use (1·005625)⁻¹²⁰ = 0·510120] (ii) Find the principal outstanding at the beginning of 61st month. [Use (1·005625)⁶⁰ = 1·400115] (iii) (a) Find the interest amount paid in the 61st instalment. OR (iii) (b) Find the principal amount paid in the 61st instalment.
[4]
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