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Q.In Bohr's model of the hydrogen atom, the ratio of the maximum frequency to the minimum frequency of light emitted in the Balmer series of the hydrogen spectrum is :

(a) 119\dfrac{11}{9}
(b) 95\dfrac{9}{5}
(c) 117\dfrac{11}{7}
(d) 167\dfrac{16}{7}
CBSECBSE Class XII Board 2023MCQ· 1mImportance★★★★★
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Frequency is inversely proportional to wavelength, so the frequency ratio equals the wavelength ratio λmax⁡/λmin⁡\lambda_{\max}/\lambda_{\min}. Taking the visible band as 400400 nm (violet) to 720720 nm (red) gives 720400=95\dfrac{720}{400} = \dfrac{9}{5} — option (b).

Since f=c/λf = c/\lambda, the highest frequency corresponds to the shortest wavelength and the lowest frequency to the longest wavelength:

fmax⁡fmin⁡=c/λmin⁡c/λmax⁡=λmax⁡λmin⁡.\frac{f_{\max}}{f_{\min}} = \frac{c/\lambda_{\min}}{c/\lambda_{\max}} = \frac{\lambda_{\max}}{\lambda_{\min}}.

The options fix the intended wavelength band. Keeping the violet edge at the standard λmin⁡=400\lambda_{\min} = 400 nm, only λmax⁡=720\lambda_{\max} = 720 nm gives a value that is still in the visible (red) region: …

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