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Q.Evaluate \int \dfrac{2 - 3\sin x}{\cos^2 x},dx.

Chhattisgarh CgbseCGBSE Intermediate Board 2026Subjective· 1mImportance★★★★★
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Split the integrand into two standard integrals, sec⁡2x\sec^2x and sec⁡xtan⁡x\sec x\tan x.

Working: Split the fraction:

∫2−3sin⁡xcos⁡2x dx=∫2cos⁡2x dx−∫3sin⁡xcos⁡2x dx=2∫sec⁡2x dx−3∫sec⁡xtan⁡x dx\int \frac{2-3\sin x}{\cos^2 x}\,dx = \int \frac{2}{\cos^2 x}\,dx - \int\frac{3\sin x}{\cos^2 x}\,dx = 2\int\sec^2x\,dx - 3\int \sec x\tan x\,dx

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