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Q.Let T be the set of all triangles in a plane, with R a relation in T given by R = {(T_1, T_2) : T_1 \text{ is congruent to } T_2}. Show that R is an equivalence relation. OR Prove that the function f : R \to R given by f(x) = 2x is one-one and onto, where R is the set of real numbers.

Chhattisgarh CgbseCGBSE Intermediate Board 2026Subjective· 5mImportance★★★★★
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Check the three defining properties of an equivalence relation — reflexivity, symmetry, transitivity — using the geometric fact that congruence of triangles has all three properties.

Setup: TT = set of all triangles in a plane. R={(T1,T2):T1 is congruent to T2}R = \{(T_1,T_2): T_1 \text{ is congruent to } T_2\}.

Reflexive: Every triangle T1T_1 is congruent to itself (trivially, by the identity correspondence of vertices, all sides and angles match). So (T1,T1)∈R(T_1,T_1)\in R for every T1∈TT_1\in T. Hence RR is reflexive.

Symmetric: Suppose (T1,T2)∈R(T_1,T_2)\in R, i.e. T1≅T2T_1\cong T_2. Congruence is a mutual correspondence of equal sides and angles, so it does not matter which triangle is named first: T2≅T1T_2\cong T_1 as well, i.e. (T2,T1)∈R(T_2,T_1)\in R. Hence RR is symmetric.

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