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Q.Using the First Principle of derivative, find the derivative of y = a^(2x+5) with respect to x.

Goa GbshseGBSHSE Class 12 Board Exam 2025Subjective· 2mImportance★★★★★
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By definition, the derivative from first principles is f′(x)=lim⁡h→0f(x+h)−f(x)hf'(x) = \displaystyle\lim_{h\to0}\dfrac{f(x+h)-f(x)}{h}. Factor out the common term and use the standard limit lim⁡t→0at−1t=ln⁡a\lim_{t\to0}\dfrac{a^t-1}{t} = \ln a.

Given: y=f(x)=a2x+5y = f(x) = a^{2x+5}

Step 1 — set up the definition:

f′(x)=lim⁡h→0a2(x+h)+5−a2x+5hf'(x) = \lim_{h\to0} \frac{a^{2(x+h)+5} - a^{2x+5}}{h}

Step 2 — factor out a2x+5a^{2x+5}:

=lim⁡h→0a2x+5(a2h−1)h=a2x+5lim⁡h→0a2h−1h= \lim_{h\to0} \frac{a^{2x+5}\left(a^{2h} - 1\right)}{h} = a^{2x+5}\lim_{h\to0}\frac{a^{2h}-1}{h}

Step 3 — evaluate the limit. Let t=2ht = 2h; as h→0h \to 0, t→0t\to 0 and h=t/2h = t/2: …

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