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Q.Find the angle between the diagonals of a parallelogram having adjacent sides a⃗ = î + 2ĵ + 3k̂ and b⃗ = 2î − 2ĵ + k̂.

Goa GbshseGBSHSE Class 12 Board Exam 2026Subjective· 2mImportance★★★★★
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The two diagonals of a parallelogram with adjacent sides a⃗,b⃗\vec a,\vec b are a⃗+b⃗\vec a+\vec b and a⃗−b⃗\vec a-\vec b; find the angle between them using the dot product.

a⃗=i^+2j^+3k^,b⃗=2i^−2j^+k^\vec a = \hat i+2\hat j+3\hat k,\quad \vec b = 2\hat i-2\hat j+\hat k

a⃗+b⃗=3i^+0j^+4k^\vec a+\vec b = 3\hat i+0\hat j+4\hat k

a⃗−b⃗=−i^+4j^+2k^\vec a-\vec b = -\hat i+4\hat j+2\hat k

Dot product: (a⃗+b⃗)⋅(a⃗−b⃗)=3(−1)+0(4)+4(2)=−3+0+8=5(\vec a+\vec b)\cdot(\vec a-\vec b) = 3(-1)+0(4)+4(2) = -3+0+8=5

∣a⃗+b⃗∣=32+02+42=25=5|\vec a+\vec b| = \sqrt{3^2+0^2+4^2}=\sqrt{25}=5

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