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Q.Monochromatic light of wavelength 589 nm is incident from air on a water surface. What are the wavelength, frequency, and speed of :

(i) Reflected light
(ii) Refracted light.
Goa GbshseGBSHSE Class 12 Board Exam 2025Subjective· 3mImportance★★★★★
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Reflection changes nothing (light stays in air); refraction keeps the frequency fixed but slows the light down and shortens its wavelength by the refractive index of water.

Given: λair=589\lambda_{air}=589 nm, refractive index of water μw≈4/3=1.33\mu_w \approx 4/3 = 1.33 (standard value), speed of light in air/vacuum c=3×108c=3\times10^8 m/s.

Frequency of the incident light:

f=cλair=3×108589×10−9≈5.09×1014 Hzf = \dfrac{c}{\lambda_{air}} = \dfrac{3\times10^8}{589\times10^{-9}} \approx 5.09\times10^{14}\ \text{Hz}

  1. Reflected light: Reflection returns the light back into the same medium (air), so its wavelength, frequency, and speed are all unchanged: λ=589 nm,f≈5.09×1014 Hz,v=3×108 m/s\lambda = 589\ \text{nm},\quad f\approx5.09\times10^{14}\ \text{Hz},\quad v=3\times10^8\ \text{m/s}
  2. Refracted light (into water): The frequency of light never changes on refraction (it's fixed by the source), so f≈5.09×1014 Hzf \approx 5.09\times10^{14}\ \text{Hz} (unchanged) The speed changes according to the refractive index: vw=cμw=3×1084/3=2.25×108 m/sv_w = \dfrac{c}{\mu_w} = \dfrac{3\times10^8}{4/3} = 2.25\times10^8\ \text{m/s} …

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