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Q.Explain dehydration reaction of alcohol to form alkene.

Gujarat GsebGSEB Higher Secondary Certificate (HSC) Examination 2023Subjective· 3mImportance★★★★★
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Acid-catalysed dehydration (E1) of an alcohol: protonate OH -> lose water (carbocation) -> lose beta-H -> alkene.

Dehydration of an alcohol is the elimination of a water molecule to form an alkene, carried out by heating the alcohol with a protic acid such as concentrated H2SO4 or H3PO4.

Example - ethanol to ethene:

CH3-CH2-OH --conc. H2SO4, 443 K--> CH2=CH2 + H2O.

Mechanism (E1, acid-catalysed):

Step 1 - Protonation: the -OH oxygen accepts a proton from the acid to form a protonated alcohol (-OH2+), converting -OH into a good leaving group (water).

Step 2 - Formation of carbocation (slow, rate-determining): the C-O bond breaks, water leaves, giving a carbocation.

Step 3 - Loss of a beta-proton: a proton is removed from a carbon adjacent (beta) to the positive carbon by a base, forming the C=C double bond (alkene) and regenerating the acid catalyst.

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