Skip to content
Question of 87

Q.How many H and O atoms are present in vanillin respectively?

(a) 8 and 4
(b) 9 and 3
(c) 9 and 4
(d) 8 and 3
Gujarat GsebGSEB Higher Secondary Certificate (HSC) Examination 2026MCQ· 1mImportance★★★★★
0% · 0/87 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Vanillin's molecular formula is C8H8O3 (4-hydroxy-3-methoxybenzaldehyde), giving 8 H atoms and 3 O atoms.

Vanillin, a naturally occurring aromatic aldehyde (the primary flavour compound of vanilla), has the structure of a benzene ring bearing three substituents: –CHO (aldehyde), –OH (hydroxyl), and –OCH3 (methoxy), with 3 remaining ring hydrogens.

Its molecular formula is C8H8O3: …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.