Skip to content
Question of 78

Q.Answer in one word/sentence: Write the formula of the compound Iron (III) sulphate.

Haryana BsehBoard of School Education Haryana (Senior Secondary Part-I / Class 11) 2025Subjective· 1mImportance★★★★★
0% · 0/78 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Cross-multiplying the charges of Fe3+^{3+} (from "Iron(III)") and SO42−_4^{2-} gives 2 iron atoms for every 3 sulphate groups.

"Iron (III)" tells us, using Stock notation, that the oxidation state (charge) of iron in this compound is +3+3, i.e. Fe3+Fe^{3+}.

Sulphate is the polyatomic ion SO42−SO_4^{2-}.

To form a neutral compound, the total positive charge must equal the total negative charge. Using the criss-cross method:

Fe3+andSO42−Fe^{3+} \quad \text{and} \quad SO_4^{2-}

…

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.