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Q.A 5 kg block is pulled over a surface with a friction coefficient of .2 with a force of 10 N. Calculate the friction force :

(a) 1 N
(b) 5 N
(c) 10 N
(d) 20 N
Haryana BsehBoard of School Education Haryana (Senior Secondary Part-I / Class 11) 2024MCQ· 1mImportance★★★★★
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Friction force = μ × Normal reaction = μmg = 10 N (using g = 10 m/s²).

For a block resting on and being pulled along a horizontal surface, the normal reaction N balances the weight:

N=mg=5×10=50 NN = mg = 5 \times 10 = 50\ \text{N}

The (kinetic) friction force opposing the block's sliding is:

f=μN=0.2×50=10 Nf = \mu N = 0.2 \times 50 = 10\ \text{N}

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