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Q.A cylindrical piece of cork of base area (A) and height h floats in a liquid of density ρ₁. The cork is depressed slightly and then released. Show that the cork oscillates up and down simple harmonically with a period T = 2π√(hρ/ρ₁g), where ρ is the density of cork. OR What is meant by stationary wave? Prove that in an open organ pipe, both odd and even harmonics are produced.

Haryana BsehBoard of School Education Haryana (Senior Secondary Part-I / Class 11) 2026Subjective· 5mImportance★★★★★
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The extra buoyant force on a slightly-depressed cork is a linear restoring force −Aρ1g y-A\rho_1 g\,y; combined with Newton's second law this gives SHM with T=2πhρ/ρ1gT=2\pi\sqrt{h\rho/\rho_1 g}.

Equilibrium: The cork (base area AA, height hh, density ρ\rho) floats in a liquid of density ρ1\rho_1. Let x0x_0 be the length submerged at equilibrium. Floating condition (weight = buoyant force):

Ahρg=Ax0ρ1g⇒x0=hρρ1A h \rho g = A x_0 \rho_1 g \quad\Rightarrow\quad x_0 = \frac{h\rho}{\rho_1}

Displaced by yy: Now push the cork down an extra small distance yy from equilibrium and release it. The submerged length becomes x0+yx_0+y, so the buoyant force becomes A(x0+y)ρ1gA(x_0+y)\rho_1 g, while the weight AhρgAh\rho g stays the same.

Net restoring force (taking downward displacement yy as positive, force taken positive upward):

F=Ahρg−A(x0+y)ρ1g=(Ahρg−Ax0ρ1g)⏟=0 at equilibrium−Aρ1g y=−Aρ1g yF = A h\rho g - A(x_0+y)\rho_1 g = \underbrace{(Ah\rho g - Ax_0\rho_1 g)}_{=0 \text{ at equilibrium}} - A\rho_1 g\, y = -A\rho_1 g\, y

So the net force is directly proportional to −y-y — exactly the signature of simple harmonic motion.

Equation of motion: The mass of the cork is m=Ahρm = Ah\rho (its own mass, constant). By Newton's second law: …

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