Angular Kinematics Derivation
Imagine a ceiling fan. When you switch it on, the blades don't just move — they rotate. A car's wheel, a spinning top, the Earth itself — all these objects turn around a fixed axis. The physics of how they turn is angular kinematics.
The Core Intuition
Linear kinematics describes motion in a straight line: position x, velocity v, acceleration a. Angular kinematics describes rotation: angular position θ, angular velocity ω, angular acceleration α.
The beautiful thing? The equations are identical in structure. Every linear quantity has an angular twin. If you know how to handle v=u+at, you already know how to handle ωf=ωi+αt — you just swap letters.
The mapping is one-to-one:
- Displacement s → Angular displacement θ (radians)
- Velocity v → Angular velocity ω (rad/s)
- Acceleration a → Angular acceleration α (rad/s²)
- Mass m → Moment of inertia I (but that's dynamics, not kinematics)
Why Radians?
Angular kinematics only works if angles are measured in radians, not degrees. Why? Because the arc length s along a circle of radius r is:
This simple relation holds only when θ is in radians. If you used degrees, you'd need an ugly conversion factor. Radians make the math clean.
Deriving the Angular Kinematics Equations
We start from the definitions, exactly as in linear kinematics.
Step 1: Angular velocity
Average angular velocity:
ωavg=ΔtΔθ
Instantaneous angular velocity (the limit as Δt→0):
ω=dtdθ
Step 2: Angular acceleration
Average angular acceleration:
αavg=ΔtΔω
Instantaneous:
α=dtdω
Step 3: Constant angular acceleration
If α is constant, we can integrate just like in linear motion.
From α=dtdω, integrate:
∫ωiωfdω=∫0tαdt
ωf−ωi=αt
ωf=ωi+αt
This is the first equation.
Step 4: Angular displacement
Since ω=dtdθ, and ω changes linearly with time (because α is constant), the average angular velocity is:
ωavg=2ωi+ωf
Then:
Δθ=ωavg⋅t=2ωi+ωf⋅t
θ=2ωi+ωft
(Here θ means Δθ, the angular displacement.)
Step 5: Displacement from initial velocity and acceleration
Substitute ωf from equation (1) into equation (2):
θ=2ωi+(ωi+αt)t=22ωi+αtt
θ=ωit+21αt2
Step 6: Velocity-displacement relation
Eliminate t from equations (1) and (3). From (1): t=αωf−ωi. Substitute into (3):
θ=ωi(αωf−ωi)+21α(αωf−ωi)2
Simplify:
θ=αωiωf−ωi2+2α(ωf−ωi)2
Multiply through by 2α:
2αθ=2ωiωf−2ωi2+ωf2−2ωiωf+ωi2
The 2ωiωf terms cancel:
2αθ=ωf2−ωi2
ωf2=ωi2+2αθ
The Four Equations of Angular Kinematics (constant α)
ωf=ωi+αt
θ=2ωi+ωft
θ=ωit+21αt2
ωf2=ωi2+2αθ
Connecting to Linear Quantities
Every point on a rotating rigid body also has linear motion. The relations are:
| Linear | Angular | Relation |
|---|
| s (arc length) | θ | s=rθ |
| v (tangential speed) | ω | v=rω |
| at (tangential acceleration) | α | at=rα |
| ac (centripetal acceleration) | ω | ac=rω2 |