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Q.Establish the relation between Torque and Moment of Inertia (in rotational motion, between torque and angular acceleration).

Haryana BsehBoard of School Education Haryana (Senior Secondary Part-I / Class 11) 2026Subjective· 2mImportance★★★★★
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Summing τi=miri2α\tau_i = m_ir_i^2\alpha over all particles of a rigid body gives the rotational analogue of Newton's second law, τ=Iα\tau=I\alpha.

Consider a rigid body rotating about a fixed axis with angular acceleration α\alpha. Take a small mass element mim_i at perpendicular distance rir_i from the axis. Its tangential (linear) acceleration is ai=riαa_i = r_i\alpha, so by Newton's second law the tangential force needed on it is Fi=miai=miriαF_i = m_i a_i = m_i r_i\alpha.

The torque produced by this force about the axis is:

τi=Fi ri=miri2α\tau_i = F_i\, r_i = m_i r_i^2 \alpha

Summing over all mass elements of the rigid body (all share the same α\alpha since the body is rigid):

τ=∑iτi=(∑imiri2)α\tau = \sum_i \tau_i = \Big(\sum_i m_i r_i^2\Big)\alpha

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