Skip to content
Question of 117

Q.The half life for radioactive decay of 14C is 5730 years. An archaeological artifact containing wood had only 80% of the 14C found in living tree. Estimate the age of the sample.

Haryana BsehBSEH Intermediate Board 2026Subjective· 3mImportance★★★★★
0% · 0/117 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Radioactive decay is always first order. Using t1/2=5730t_{1/2}=5730 years to find kk, then the first-order time equation with 80% of 14C^{14}C remaining gives an age of about 1846 years.

Step 1: Find the rate constant kk.

Radioactive decay follows first-order kinetics, so:

k=0.693t1/2=0.6935730 yr=1.209×10−4 yr−1k = \dfrac{0.693}{t_{1/2}} = \dfrac{0.693}{5730\ \text{yr}} = 1.209 \times 10^{-4}\ \text{yr}^{-1}

Step 2: Apply the first-order integrated rate law.

Let [A]0=100[A]_0 = 100 (initial, in a living tree) and [A]=80[A] = 80 (found in the artifact, 80% remaining): …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.