Skip to content
Question of 90

Q.Benzene reacts with methyl chloride in presence of anhydrous AlCl3 to form:

(a) Chlorobenzene
(b) Benzyl chloride
(c) Xylene
(d) Toluene
Himachal HpboseHPBOSE Himachal Pradesh Class 11 Board Exam 2024MCQ· 1mImportance★★★★★
0% · 0/90 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Benzene + CH3Cl in the presence of anhydrous AlCl3 undergoes Friedel-Crafts alkylation to give toluene (methylbenzene).

This is the Friedel-Crafts alkylation reaction, one of the key electrophilic aromatic substitution reactions of benzene:

C6H6+CH3Cl→anhydrous AlCl3C6H5−CH3+HClC_6H_6 + CH_3Cl \xrightarrow{\text{anhydrous } AlCl_3} C_6H_5-CH_3 + HCl

Mechanism outline:

  1. Anhydrous AlCl3 (a Lewis acid) coordinates with the chlorine of CH3Cl, polarising and eventually breaking the C-Cl bond to generate an electrophilic methyl carbocation-like species, CH3^+ (as part of a complex, CH3−AlCl4−CH_3-AlCl_4^-).
  2. This electrophile attacks the electron-rich benzene ring, forming a resonance-stabilised arenium (sigma-complex) intermediate.
  3. Loss of a proton (H^+) from the sp3 carbon restores the aromatic ring, giving toluene, and regenerates the AlCl3 catalyst along with HCl. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.