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Q.(a) Explain disproportionation reaction and combination reaction.

(2)
(b) Define Reducing agents. (1)
Himachal HpboseHPBOSE Himachal Pradesh Class 11 Board Exam 2024Subjective· 3mImportance★★★★★
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Disproportionation is self-oxidation-and-reduction of the same element; a combination reaction forms one product from several reactants (and is redox when elements are involved); a reducing agent is the electron donor in a redox reaction, and it gets oxidised in the process.

(a) Disproportionation reaction:

A disproportionation reaction is a special type of redox reaction in which a single species, containing an element in one intermediate oxidation state, is simultaneously oxidised and reduced — i.e., that one species acts as both the oxidising agent and the reducing agent, producing two different oxidation states of the same element among the products.

Example: Copper(I) ions in aqueous solution are unstable and disproportionate:

2Cu+(aq)→Cu2+(aq)+Cu(s)2Cu^+(aq) \rightarrow Cu^{2+}(aq) + Cu(s)

Here Cu(+1) is oxidised to Cu(+2) and simultaneously reduced to Cu(0).

Another classic example:

Cl2(g)+2OH−(aq)→Cl−(aq)+ClO−(aq)+H2O(l)Cl_2(g) + 2OH^-(aq) \rightarrow Cl^-(aq) + ClO^-(aq) + H_2O(l)

Here Cl(0) in Cl2 is disproportionated into Cl(-1) (chloride) and Cl(+1) (hypochlorite).

Combination reaction:

A combination reaction is one in which two or more reactants (elements and/or compounds) combine to form a single product. When at least one of the reactants is a free element, the reaction is usually also a redox reaction, since the element's oxidation number changes from 0 to some non-zero value.

Example:

C(s)+O2(g)→CO2(g)C(s) + O_2(g) \rightarrow CO_2(g)

Here carbon's oxidation number changes from 0 to +4 (oxidised) and oxygen's changes from 0 to -2 (reduced) — a redox combination reaction.

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