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Q.Without using distance formula, show that points (−2,−1)(-2,-1), (4,0)(4,0), (3,3)(3,3) and (−3,2)(-3,2) are the vertices of a Parallelogram. OR The line through the points (h,3)(h, 3) and (4,1)(4, 1) intersects the line 7x−9y−19=07x - 9y - 19 = 0 at right angles. Find the value of hh.

Himachal HpboseHPBOSE Himachal Pradesh Class 11 Board Exam 2024Subjective· 3mImportance★★★★★
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The diagonals ACAC and BDBD share the same midpoint, so the diagonals bisect each other — a property unique to parallelograms.

Let A(−2,−1)A(-2,-1), B(4,0)B(4,0), C(3,3)C(3,3), D(−3,2)D(-3,2) be the points taken in order.

Key fact (no distance formula needed): a quadrilateral is a parallelogram if and only if its diagonals bisect each other, i.e. the midpoint of one diagonal equals the midpoint of the other.

Midpoint formula: for points (x1,y1)(x_1,y_1) and (x2,y2)(x_2,y_2), the midpoint is (x1+x22,y1+y22)\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right).

Midpoint of diagonal ACAC:

(−2+32,−1+32)=(12, 1).\left(\dfrac{-2+3}{2},\dfrac{-1+3}{2}\right)=\left(\dfrac12,\ 1\right).

Midpoint of diagonal BDBD:

(4+(−3)2,0+22)=(12, 1).\left(\dfrac{4+(-3)}{2},\dfrac{0+2}{2}\right)=\left(\dfrac12,\ 1\right).

Both diagonals have the same midpoint (12,1)\left(\dfrac12,1\right), so they bisect each other. Therefore ABCDABCD is a parallelogram.

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