Skip to content
Question of 50

Q.Based on the radioactive-decay passage above (Q.8): In alpha (α) decay, A is mass number and Z is atomic number.

(a) A decreases by 4 and Z increases by 2
(b) A decreases by 4 and Z decreases by 2
(c) A increases by 4 and Z decreases by 2
(d) A increases by 4 and Z increases by 2.
Himachal HpboseHPBOSE Plus Two Board 2023MCQ· 1mImportance★★★★★
0% · 0/50 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

An alpha particle is a helium nucleus, 2He4{}_2\text{He}^4, so emitting one removes 4 from the mass number and 2 from the atomic number.

Alpha decay is the emission of an alpha particle, 2He4{}_2\text{He}^4, which itself has mass number 4 and atomic number (charge number) 2. By conservation of A and Z (as stated in the passage):

ZXA→Z−2YA−4+2He4 {}_Z X^A \to {}_{Z-2}Y^{A-4} + {}_2\text{He}^4 …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.