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Question of 20
Q.

Compute mode of the following series :

Mid valuesFrequency
57
1013
1519
2024
2532
3028
3517
408
456

OR

Calculate arithmetic mean of the following series by using Step Deviation Method :

Class IntervalFrequency
5-158
15-2512
25-3515
35-459
45-556
Jammu Kashmir JkboseJKBOSE Class 11 (Commerce) 2025Subjective· 4mImportance★★★★★est
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Mode of the mid-value series ≈ 25.83.

Step 1 — Convert mid-values to class intervals. Since consecutive mid-values differ by 5, the class width h=5h = 5, and each class boundary is (mid-value ± 2.5):

Mid valueClass IntervalFrequency (f)
52.5–7.57
107.5–12.513
1512.5–17.519
2017.5–22.524
2522.5–27.532 ← highest frequency
3027.5–32.528
3532.5–37.517
4037.5–42.58
4542.5–47.56

Step 2 — Identify the modal class. The highest frequency is 32, at the class 22.5–27.5. So:

l=22.5l = 22.5 (lower limit of modal class), f1=32f_1 = 32 (modal class frequency), f0=24f_0 = 24 (frequency of class preceding modal class), f2=28f_2 = 28 (frequency of class succeeding modal class), h=5h = 5.

Step 3 — Apply the mode formula:

Mode=l+f1−f02f1−f0−f2×hMode = l + \dfrac{f_1 - f_0}{2f_1 - f_0 - f_2} \times h

=22.5+32−242(32)−24−28×5=22.5+864−52×5=22.5+812×5= 22.5 + \dfrac{32-24}{2(32)-24-28}\times 5 = 22.5 + \dfrac{8}{64-52}\times 5 = 22.5 + \dfrac{8}{12}\times 5

=22.5+3.33=25.83= 22.5 + 3.33 = 25.83

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