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Q.In the expansion of (1+a)m+n(1 + a)^{m+n}, prove that coefficients of ama^m and ana^n are equal. OR Find the 13th term in the expansion of (9x−13x)18\left(9x - \dfrac{1}{3\sqrt{x}}\right)^{18}, x≠0x \neq 0.

Jammu Kashmir JkboseJammu and Kashmir Board of School Education (Class 11) 2023Subjective· 4mImportance★★★★★
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The coefficients of ama^m and ana^n in (1+a)m+n(1+a)^{m+n} are (m+nm)\binom{m+n}{m} and (m+nn)\binom{m+n}{n} respectively, and these binomial coefficients are always equal by symmetry.

The general (i.e. (r+1)(r+1)th) term in the expansion of (1+a)m+n(1+a)^{m+n} is

Tr+1=(m+nr)arT_{r+1} = \binom{m+n}{r}a^r

Coefficient of ama^m (put r=mr=m): (m+nm)\binom{m+n}{m}

Coefficient of ana^n (put r=nr=n): (m+nn)\binom{m+n}{n}

Using the identity (Nk)=(NN−k)\binom{N}{k}=\binom{N}{N-k} with N=m+nN=m+n: since N−m=nN-m = n,

(m+nm)=(m+nn)\binom{m+n}{m} = \binom{m+n}{n}

Hence the coefficients of ama^m and ana^n are equal.

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