Skip to content
Question of 175

Q.If y=4x+5sin⁡x3x+7cos⁡xy = \dfrac{4x + 5\sin x}{3x + 7\cos x}, find dydx\dfrac{dy}{dx}.

Jammu Kashmir JkboseJammu and Kashmir Board of School Education (Class 11) 2024Subjective· 4mImportance★★★★★
0% · 0/175 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Use the quotient rule (uv)′=u′v−uv′v2\left(\dfrac uv\right)'=\dfrac{u'v-uv'}{v^2} with u=4x+5sin⁡xu=4x+5\sin x, v=3x+7cos⁡xv=3x+7\cos x, then simplify using sin⁡2x+cos⁡2x=1\sin^2x+\cos^2x=1.

Let u=4x+5sin⁡xu = 4x + 5\sin x and v=3x+7cos⁡xv = 3x + 7\cos x, so y=uvy = \dfrac{u}{v}.

u′=4+5cos⁡x,v′=3−7sin⁡xu' = 4 + 5\cos x, \qquad v' = 3 - 7\sin x

By the quotient rule:

dydx=u′v−uv′v2=(4+5cos⁡x)(3x+7cos⁡x)−(4x+5sin⁡x)(3−7sin⁡x)(3x+7cos⁡x)2\dfrac{dy}{dx} = \dfrac{u'v - uv'}{v^2} = \dfrac{(4+5\cos x)(3x+7\cos x) - (4x+5\sin x)(3-7\sin x)}{(3x+7\cos x)^2}

Expand the numerator:

(4+5cos⁡x)(3x+7cos⁡x)=12x+28cos⁡x+15xcos⁡x+35cos⁡2x(4+5\cos x)(3x+7\cos x) = 12x + 28\cos x + 15x\cos x + 35\cos^2x

(4x+5sin⁡x)(3−7sin⁡x)=12x−28xsin⁡x+15sin⁡x−35sin⁡2x(4x+5\sin x)(3-7\sin x) = 12x - 28x\sin x + 15\sin x - 35\sin^2x

Subtracting the second from the first: …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.